John Guiver replied on 08-22-2009 3:37 AM
Hi Freddy
There is no short cut method for Variable.Dirichlet which takes a variable argument. Recommended method is as below which uses the unary ‘Random’
factor. (In addition, it is better to make prior an Observed rather than a Constant, so it doesn’t get compiled into the code – let me know if you need help with that).
John
static void Main(string[] args)
{
Range two = new
Range(2).Named("two");
Range five = new
Range(5).Named("five");
VariableArray2D<Vector> behaviour =
Variable.Array<Vector>(two, five);
Dirichlet[,] dir = new
Dirichlet[,]
{
{
new Dirichlet(new
double[]{ 1, 0, 0, 0, 0 }),
new Dirichlet(new
double[]{ 2, 1, 0, 0, 0 }),
new Dirichlet(new
double[]{ 3, 2, 1, 0, 0 }),
new Dirichlet(new
double[]{ 4, 3, 2, 1, 0 }),
new Dirichlet(new
double[]{ 5, 4, 3, 2, 1 })
}, {
new Dirichlet(new
double[]{ 1, 2, 3, 4, 5 }),
new Dirichlet(new
double[]{ 0, 1, 2, 3, 4 }),
new Dirichlet(new
double[]{ 0, 0, 1, 2, 3 }),
new Dirichlet(new
double[]{ 0, 0, 0, 1, 2 }),
new Dirichlet(new
double[]{ 0, 0, 0, 0, 1 })
}
};
VariableArray2D<Dirichlet> prior =
Variable.Constant(dir, two, five).Named("prior");
using (Variable.ForEach(two))
{
using (Variable.ForEach(five))
{
behaviour[two, five] =
Variable.Random<Vector,
Dirichlet>(prior[two,five]);
}
}
Console.WriteLine("Press any key to exit.");
System.Console.ReadKey();
}
