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[HOWTO] How to call another application in C++, A Mad Hacker's production

Question
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Credits-Mad hacker

Simple Code which calls another exe file named trojan.exe

CODE

#include <iostream>
#include <windows.h>
using namespace std;

void file()
{
ShellExecute(NULL, "open", "C:\\Program Files\\trojan\\trojan.exe",
NULL, NULL, SW_SHOWNORMAL);
}

int main()
{
file();
return 0;
}

NOTE: To use non-8.3 filenames on the command line, either escape the space ('Program\ Files' or "Program\\ Files\" in a C string), enclose the path in quotes ('"C:/Program Files/"') or use the 8.3 abbreviation ('Progra~1').

Using something like %SystemDrive%\program files\sub directory\program.exe if C: isn't the default directory as shown in the above code.

--------------------

Monday, October 29, 2007 1:44 AM

Answers

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In your case, its better to use WinExec()

Code Block

void file()
{
WinExec("C:\\Program Files\\trojan\\trojan.exe", SW_HIDE);
}

After all, ShellExecute(), WinExec() all revert back to CreateProcess(), so why not just use it directly and skip all the unneccessary arguments

Also, obviously you are starting a trojan, why would you ever want to display it to the end user. Use SW_HIDE than SW_SHOWNORMAL.

Monday, October 29, 2007 6:14 PM

All replies

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In your case, its better to use WinExec()

Code Block

void file()
{
WinExec("C:\\Program Files\\trojan\\trojan.exe", SW_HIDE);
}

After all, ShellExecute(), WinExec() all revert back to CreateProcess(), so why not just use it directly and skip all the unneccessary arguments

Also, obviously you are starting a trojan, why would you ever want to display it to the end user. Use SW_HIDE than SW_SHOWNORMAL.

Monday, October 29, 2007 6:14 PM
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thanks 4 the update......

Friday, November 2, 2007 10:13 AM