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Is the course 2710 still relevant or is there an upgraded course exist?

Question
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Just wondering whether there is a new version of this course with .net 3.5/4.0 and all new products. This course seems to be pretty old, not sure if the contents are upgraded.
Friday, February 10, 2012 7:42 PM
Answers
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The reason why this course hasn't been updated is because the certification associated with this course (70-300) has been retired i.e. is no longer available.
As far as I know, no course has been developed to replace this one.
Jeff Wharton
MSysDev (C.Sturt), MDbDsgnMgt (C.Sturt), MCT, MCPD, MCITP, MCDBA
Blog: Mr. Wharty's Ramblings
MC ID: Microsoft Transcript
Please mark answered if I've answered your question and vote for it as helpful to help other user's find a solution quicker- Proposed as answer by Rich Prescott Saturday, February 11, 2012 1:58 AM
- Marked as answer by Horizon_NetEditor Thursday, February 23, 2012 10:17 AM
Friday, February 10, 2012 11:28 PM
All replies
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The reason why this course hasn't been updated is because the certification associated with this course (70-300) has been retired i.e. is no longer available.
As far as I know, no course has been developed to replace this one.
Jeff Wharton
MSysDev (C.Sturt), MDbDsgnMgt (C.Sturt), MCT, MCPD, MCITP, MCDBA
Blog: Mr. Wharty's Ramblings
MC ID: Microsoft Transcript
Please mark answered if I've answered your question and vote for it as helpful to help other user's find a solution quicker- Proposed as answer by Rich Prescott Saturday, February 11, 2012 1:58 AM
- Marked as answer by Horizon_NetEditor Thursday, February 23, 2012 10:17 AM
Friday, February 10, 2012 11:28 PM -
What would you recommend a person taking instead? Any other course exist relating to Analyzing requirement and Defining .Net solution? Thanks much.Monday, February 13, 2012 3:08 PM
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No there is no other course that covers this information
Jeff Wharton
MSysDev (C.Sturt), MDbDsgnMgt (C.Sturt), MCT, MCPD, MCITP, MCDBA
Blog: Mr. Wharty's Ramblings
MC ID: Microsoft Transcript
Please mark answered if I've answered your question and vote for it as helpful to help other user's find a solution quickerThursday, February 16, 2012 11:24 PM