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so ..........i m going to paste Question and Ans , for TCS Apti ........

Enjoy Guys ..........

Monday, May 21, 2007 7:17 PM

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if there is any mistake in ans , then plz correct them

TC

Monday, May 21, 2007 7:18 PM
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I lost Rs.68 in two races. My second race loss is Rs.6 more than the first race. My friend lost Rs.4 more than me in the second race. What is the amount lost by my friend in the second race?

Ans

Ans : 41

first race loss = x
second race loss = y

Cond 1 : x+y = 68

Cond 2 : y = x + 6

Simultaneous eq. needs to be solved.

Monday, May 21, 2007 7:24 PM
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(1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

Ans

5/6*6/7*7/8*8/9--------------n+3/n+4*n+4/n+5 all the terms cancel out each other and remainder will be ans ----- 5/n+5

Monday, May 21, 2007 7:27 PM
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A face of the clock is divided into three parts. First part hours total is equal to the sum of the second and third part. What is the total of hours in the bigger part?

Ans

let x be the bigger part y and z are smaller parts
x+y+z=78 and x=y+z so sub y+z=x in x+y+z=78 we get 2x=78
so x=78/2=39
Ans is 39

Monday, May 21, 2007 7:30 PM
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ONE RECTANGULAR PLATE WITH LENGTH 8INCHES, BREADTH 11 INCHES AND 2 INCHES THICKNESS IS THERE.WHAT IS THE LENGTH OF THE CIRCULAR ROD WITH DIAMETER 8 INCHES AND EQUAL TO VOLUME OF RECTANGULAR PLATE?

Ans

vol. of rect. plate= 8*11*2=176

area of rod=(22/7)*(8/2)*(8/2)=(352/7)

vol. of rod=area*length=vol. of plate

so length of rod= vol of plate/area=176/(352/7)=3.5

Monday, May 21, 2007 7:32 PM
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In some game 139 members have participated every time one fellow will get bye what is the number of matches to choose the champion to be held?

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the answer is 138 matches

explanationince one player gets a bye in each round,he will reach the finals of the tournament without playing a match.

therefore 137 matches should be played to detemine the second finalist from the remaining 138 players(excluding the 1st player)

therefore to determine the winner 138 matches shd be played.

Monday, May 21, 2007 7:34 PM
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One fast typist type some matter in 2hr and another slow typist type the same matter in 3hr. If both do combinely in how much time they will finish.

Ans

Faster one can do 1/2 of work in one hourslower one can do 1/3 of work in one hourboth they do (1/2+1/3=5/6) th work in one hour.so work will b finished in 6/5=1.2 hour i e 1 hour 12 min.

Monday, May 21, 2007 7:36 PM

In 8*8 chess board what is the total number of squares refers odel

Ans

There are 204 squares on the board We found that you would add the different squares - 1 + 4 + 9 + 16+ 25 + 36 + 49 + 64.

Also in 3*3 tic tac toe board what is the total no of squares

Ans 14 ie 9+4(bigger ones)+1 (biggest one)

If you ger 100*100 board just use the formula

the formula for the sum of the first n perfect squares is

                        n x (n + 1) x (2n + 1)

                        ______________________

if in this formula if you put n=8 you get your answer 204

Monday, May 21, 2007 7:38 PM

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2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?

Ans

hi,

i think

it can be 15 bcoz

2x+3y+4z=15

3x+2y+z=10

adding

5x+5y+5z=25

x+y+z=5 that is for 1 orange ,1 bannana and 1 apple requires 5Rs.

so for 3 orange ,3 bannana and 3 apple requires 15Rs.

i.e. 3x+3y+3z=15........

Monday, May 21, 2007 7:40 PM
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2 pencils costs 8 cents, then 5 pencils cost how much (Funny question )

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Monday, May 21, 2007 7:47 PM
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A work is done by the people in 24 min. One of them can do this work alone in 40 min. How much time required to do the same work for the second person

Ans

Two people work together in 24 mins.

So, their one day work is

(1/A)+(1+B)=(1/24)

One man can complete the work in 40mins

one man's one day work (1/B)= (1/40)

Now,

(1/A)=(1/24)-(1/40)

(1/A)=(1/60)

So, A can complete the work in 60 mins.

Monday, May 21, 2007 7:50 PM
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A car is filled with four and half gallons of oil for full round trip. Fuel is taken 1/4 gallons more in going than coming. What is the fuel consumed in coming up.

Ans

lets assume while coming it takes x gallons.then while going it takes (x+1/4)gallons.then

x+(x+1/4)=4.5

2x=4.5-.25=4.25

x=4.25/2=2.125

x=2.125

Monday, May 21, 2007 7:53 PM

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if there is any mistake in ans , then plz correct them

TC

Monday, May 21, 2007 7:18 PM
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I lost Rs.68 in two races. My second race loss is Rs.6 more than the first race. My friend lost Rs.4 more than me in the second race. What is the amount lost by my friend in the second race?

Ans

Ans : 41

first race loss = x
second race loss = y

Cond 1 : x+y = 68

Cond 2 : y = x + 6

Simultaneous eq. needs to be solved.

Monday, May 21, 2007 7:24 PM
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(1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

Ans

5/6*6/7*7/8*8/9--------------n+3/n+4*n+4/n+5 all the terms cancel out each other and remainder will be ans ----- 5/n+5

Monday, May 21, 2007 7:27 PM
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A face of the clock is divided into three parts. First part hours total is equal to the sum of the second and third part. What is the total of hours in the bigger part?

Ans

let x be the bigger part y and z are smaller parts
x+y+z=78 and x=y+z so sub y+z=x in x+y+z=78 we get 2x=78
so x=78/2=39
Ans is 39

Monday, May 21, 2007 7:30 PM
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ONE RECTANGULAR PLATE WITH LENGTH 8INCHES, BREADTH 11 INCHES AND 2 INCHES THICKNESS IS THERE.WHAT IS THE LENGTH OF THE CIRCULAR ROD WITH DIAMETER 8 INCHES AND EQUAL TO VOLUME OF RECTANGULAR PLATE?

Ans

vol. of rect. plate= 8*11*2=176

area of rod=(22/7)*(8/2)*(8/2)=(352/7)

vol. of rod=area*length=vol. of plate

so length of rod= vol of plate/area=176/(352/7)=3.5

Monday, May 21, 2007 7:32 PM
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In some game 139 members have participated every time one fellow will get bye what is the number of matches to choose the champion to be held?

Ans

the answer is 138 matches

explanationince one player gets a bye in each round,he will reach the finals of the tournament without playing a match.

therefore 137 matches should be played to detemine the second finalist from the remaining 138 players(excluding the 1st player)

therefore to determine the winner 138 matches shd be played.

Monday, May 21, 2007 7:34 PM
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One fast typist type some matter in 2hr and another slow typist type the same matter in 3hr. If both do combinely in how much time they will finish.

Ans

Faster one can do 1/2 of work in one hourslower one can do 1/3 of work in one hourboth they do (1/2+1/3=5/6) th work in one hour.so work will b finished in 6/5=1.2 hour i e 1 hour 12 min.

Monday, May 21, 2007 7:36 PM